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=15B-5-6B^2+2B*4
We move all terms to the left:
-(15B-5-6B^2+2B*4)=0
We get rid of parentheses
6B^2-15B-2B*4+5=0
Wy multiply elements
6B^2-15B-8B+5=0
We add all the numbers together, and all the variables
6B^2-23B+5=0
a = 6; b = -23; c = +5;
Δ = b2-4ac
Δ = -232-4·6·5
Δ = 409
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$B_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$B_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$B_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-23)-\sqrt{409}}{2*6}=\frac{23-\sqrt{409}}{12} $$B_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-23)+\sqrt{409}}{2*6}=\frac{23+\sqrt{409}}{12} $
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